This calculator will allow you to find any missing quantity in a joint variation though a single click. For this, you have to identify which quantities are directly proportional to the missing quantity (and write them in the straight order) and which ones are inversely proportional to the missing quantity (and write them in the reverse order). For example, if the quantity to be calculated is a2 where a1 is given and if the quantity a varies directly as b, d and e and inversely as c and f, we write the resulting joint variation as
Joint Variation Calculator Parameters: when entering Indirect Variation it is important to remember that the fraction is inversed, so, if you have an input fraction of 2/5 you would enter 5/2 as the fraction is inversed.
Quantity to be calculated Inputs | |
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(a1) /(a2) | |
Direct Variation Inputs | |
(b1) /(b2) | |
Indirect Variation Inputs | |
(m2)/(m1) | |
Joint Variation = |
Joint Variation Formula and Calculations |
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a1/a2 = b1/b2 ∙ m2/m1 /x = / ∙ / /x = / x = × / x = / x = |
Joint Variation Calculator Input Values |
Quantity to be calculated (a) /x |
Direct Variation Inputs |
Input (b) / |
Indirect Variation Inputs |
Input (m) / |
Please note that the formula for each calculation along with detailed calculations is shown further below this page. As you enter the specific factors of each joint variation calculation, the Joint Variation Calculator will automatically calculate the results and update the formula elements with each element of the joint variation calculation. You can then email or print this joint variation calculation as required for later use.
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In mathematics, variation is defined by any change in a quantity due to the change of another quantity. As a concept, variation is very similar to proportion. Here are some differences between proportion and variation:
There are three types of variation between two quantities x and y:
One must be careful to identify the quantities that are in direct variation and the ones in inverse variation. Let's consider an example.
Five men can repair 60 machines in 4 days. How many machines can two men repair in 15 days?
First, let's analyse the situation. We will consider the quantities two by two by assuming the third one as constant.
Writing this joint variation for two situations (1) and (2), we obtain
We have to calculate y2. Thus, substituting the known values, we obtain
Simplifying by 10 the fraction on the right for easier operations, we obtain
Thus,
You can start from the quantity that is to be calculated, regardless the type of variation involved. In this case, any inverse variation is written by inverting the variables. Thus, if in the above example the number of men x2 needed to repair 90 machines in 15 days were unknown given the same initial conditions, we would write
Substituting the values, we obtain
The following Math tutorials are provided within the Ratio and Proportion section of our Free Math Tutorials. Each Ratio and Proportion tutorial includes detailed Ratio and Proportion formula and example of how to calculate and resolve specific Ratio and Proportion questions and problems. At the end of each Ratio and Proportion tutorial you will find Ratio and Proportion revision questions with a hidden answer that reveal when clicked. This allows you to learn about Ratio and Proportion and test your knowledge of Math by answering the revision questions on Ratio and Proportion.
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