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Math Lesson 13.4.7 - Modelling the Exponential Curve using Natural Logarithm

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Welcome to our Math lesson on Modelling the Exponential Curve using Natural Logarithm, this is the seventh lesson of our suite of math lessons covering the topic of Natural Logarithm Function and Its Graph, you can find links to the other lessons within this tutorial and access additional Math learning resources below this lesson.

Modelling the Exponential Curve using Natural Logarithm

In the previous tutorial, we explained that modelling an exponential curve means converting the graph of any exponential function into a linear one. This is also true for functions of the form

y(x) = aebx

where a and b are coefficients (numbers) and x is the independent variable.

The procedure is similar to that used for modelling curves of the form

y = k ∙ ax

explained in the previous tutorial. Thus, first we take the 'ln' off both sides so we can remove Euler's Number e; then, we calculate the values of the new variables. After this step is complete, we plot the linear graph obtained by replacing the old x- and y-values with the ln x and ln y ones in a ln y vs ln x graph. For this, the function is transformed in the following way:

y = a ∙ ebx
ln y = ln (a ∙ ebx )
ln y = ln a + ln ebx
ln y = ln a + bx ∙ ln e
ln y = ln a + bx ∙ 1
ln y = bx + ln a

The last form of this function is similar to that of the linear function

y = mx + n

where in our case, b represents the gradient of the line and ln a is the constant.

Let's consider an example to clarify this point.

Example 3

The number of bacteria present in a laboratory sample taken from a patients blood after the start of his cure is given by the function

y(x) = 3000 ∙ e-1.4x

where y is the number of bacteria in the sample and x is the number of days after starting the cure.

  1. Plot a linear graph that depicts the relationship between the bacteria present in the blood sample and the number of days elapsed since the start of the cure to the 5th day.
  2. The patient is considered as healed when the number of bacteria in the sample is less than 20. How long does it take for this process?

Solution 3

  1. First, we transform the original function into a linear one. We have
    y(x) = 3000 ∙ e-1.4x
    ln y = ln (3000 ∙ e-1.4x)
    ln y = ln 3000 + ln e-1.4x
    ln y = ln 3000 - 1.4x ln e
    ln y = ln 3000 - 1.4x
    Now, we make a table using the above formula to show the linear relationship between the two variables. Since we don't have the values of y, we can make a table containing three rows instead of two separate tables, as we don't need the values of ln x but only those of x. Thus, the first row is for the variable x, the second row for the variable y and the third row for ln y. We have Math Tutorials: Natural Logarithm Function and Its Graph Example The ln y vs x graph for this relation is shown in the figure below. Math Tutorials: Natural Logarithm Function and Its Graph Example The above graph clearly shows the linear relationship required.
  2. From the data found in the second row, it is clear that the patient is considered as healed in the fourth day of starting the cure, as in this day the number of bacteria present in the sample falls below 20.

More Natural Logarithm Function and Its Graph Lessons and Learning Resources

Logarithms Learning Material
Tutorial IDMath Tutorial TitleTutorialVideo
Tutorial
Revision
Notes
Revision
Questions
13.4Natural Logarithm Function and Its Graph
Lesson IDMath Lesson TitleLessonVideo
Lesson
13.4.1Understanding Euler's Number
13.4.2The History of Euler's Number
13.4.3Definition of Natural Logarithm
13.4.4Natural Logarithm Rules
13.4.5Equations Involving Natural Logarithm
13.4.6The Natural Logarithm Function and its Graph
13.4.7Modelling the Exponential Curve using Natural Logarithm

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  7. Continuing learning logarithms - read our next math tutorial: Definition and Properties of Logarithms

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