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Welcome to our Math lesson on Solving a Quadratic Equation by Completing the Square, this is the fourth lesson of our suite of math lessons covering the topic of Quadratic Equations, you can find links to the other lessons within this tutorial and access additional Math learning resources below this lesson.
So far, we tried to solve a quadratic equation by trying to guess the coefficients and constant of the binomial expression. However, it was a bit challenging to find the right values, as we had to also take into account the rest of the expression, which must also fit the binomial expression. Another limitation of our reasoning consists of the fact that the coefficient a is not always a perfect square. Therefore, we must find a standard method for solving quadratic equations, that consists of completing the square. We must therefore try to express a given quadratic equation
in the form
where p and q are numbers.
The procedure applied to complete the square is as follows:
Step 1: First of all, we find the expression in the brackets. For this, we must express the squared part in the form
where b is the coefficient preceding x in the original equation. Thus, it is obvious that p = B/2.
Step 2: Expanding the last expression yields
Step 3: Check the difference between the old and new constant.
For example, in the equation x2 - 4x + 3 = 0, we have a = 1, b = -4 and c = 3. Thus,
Given that the original equation is
we have q = -1 because
Therefore, the original quadratic equation is factorized by completing the square as
You may wonder why one needs to complete the square in quadratic equations. In fact, completing the square gives us the possibility to solve the quadratic equation by solving two first - order equations with one variable. In our example, we have
Thus, since √1 = -1 or +1, we obtain two different first - order equations with one variable:
and
The first equation gives x1 = - 1 + 2 = 1, while the second one gives x2 = 1 + 2 = 3.
Solve the following quadratic equations by completing the square.
Remark! You can quickly check your work by substituting the roots found in the original equation. Thus, since the roots in the exercise 4a were - 1 and 3, we have
and
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