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Math Lesson 9.6.1 - Quadratic Formula Definition

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Welcome to our Math lesson on Quadratic Formula Definition, this is the first lesson of our suite of math lessons covering the topic of The Quadratic Formula, you can find links to the other lessons within this tutorial and access additional Math learning resources below this lesson.

The Quadratic Formula

From tutorials 6.4 and 9.5, it is known that the general form of a quadratic equation is

ax2 + bx + c = 0

where a and b are the coefficients (numbers followed by variables) of this equation while c is a constant (a number alone, with no variable after it).

In the previous tutorial, we explained a nice method for solving quadratic equations, that consists of completing the square. According to this method, we have to represent the expression in brackets in the form

(x + b/2)2

Now, let's try to express the general form of a quadratic equation in such a way that fits the completing - the - square form. We have:

ax2 + bx + c = 0
a(x2 + b/a x) + c = 0
a(x + B/2a)2 + c - b2/4a = 0

(This is because

(x + b/2a)2 = x2 - 2b/2a x + b2/4a2 = x2 - b/a x + b2/4a2

)

From the last equation, we can write

a(x + b/2a)2 = b2/4a - c

or

a(x + b/2a)2 = b2/4a - 4ac/4a

or

a(x + b/2a)2 = b2 - 4ac/4a

Dividing both sides by a yields

(x + B/2a)2 = b2 - 4ac/4a2

Taking the square root of both sides in the last equation yields

(x + b/2a)2 = √b2 - 4ac/4a2

or

x + b/2a = ± √b2 - 4ac/4a2

or

x = - B/2a ± √b2 - 4ac/4a2
= - b/2a ± b2 - 4ac/4a2
= - b/2a ± b2 - 4ac/2a
= - b ± √b2 - 4ac/2a

In this way, we obtain two possible solutions for a quadratic equation:

x1 = - b - √b2 - 4ac/2a

and

x2 = - b + √b2 - 4ac/2a

The mathematical sentence

x = - b ± √b2 - 4ac/2a

is known as the quadratic formula that allows us to solve any quadratic equation or detect immediately when a quadratic equation cannot be solved.

Example 1

Solve the equation

2x2 + 5x + 3 = 0

using the quadratic formula and eventually check your solution by completing the square. Which method is simpler?

Solution 1

All quadratic equations have a general form of

ax2 + bx + c = 0

Since our equation is

2x2 + 5x + 3 = 0

we have a = 2, b = 5 and c = 3.

Using the quadratic formula yields

x1 = - b - √b2 - 4ac/2a
= 5 - √52 - 4 ∙ 2 ∙ 3/2 ∙ 2
= - 5 - √25 - 24/4
= - 5 - √1/4
= - 5 - 1/4
= - 6/4
= - 3/2

and

x2 = - b + √b2 - 4ac/2a
= - 5 + √52 - 4 ∙ 2 ∙ 3/2 ∙ 2
= - 5 + √25 - 24/4
= - 5 + √1/4
= - 5 + 1/4
= - 4/4
= - 1

Now, let's check the solution by completing the square. But first, we have to express the original equation in the form

x2 + bx + c = 0

We have to divide all terms of the original equation by 2 therefore. Thus, from

2x2 + 5x + 3 = 0

we obtain

x2 + 5/2 x + 3/2 = 0

Now, we have new coefficients for our equation: a = 1, b = 5/2 and c = 3/2. Let's write the expression in brackets that helps complete the square. Thus,

(x + B/2)2
= x + 5/2 ∙ 22
x2 + 2 ∙ x ∙ 5/4 + (5/4)2
= x2 + 10/4 x + 25/16
= x2 + 5/2 x + 25/16

Since the simplified original equation is

x2 + 5/2 x + 3/2 = 0

or

x2 + 5/2 x + 24/16 = 0

we obtain

(x2 + 5/2 x + 25/16) - 1/16 = 0
(x + 5/4)2 - (1/4)2 = 0
(x + 5/4)2 = (1/4)2
x + 5/4 = ± 1/4

Thus,

x1 = - 1/4 - 5/4
= - 6/4
= - 3/2

and

x2 = 1/4 - 5/4
= - 4/4
= - 1

As you see, the two roots are the same as those found by using the quadratic formula, but obtained through a longer procedure. Therefore, the advantages of using the quadratic formula are now evident.

More The Quadratic Formula Lessons and Learning Resources

Equations Learning Material
Tutorial IDMath Tutorial TitleTutorialVideo
Tutorial
Revision
Notes
Revision
Questions
9.6The Quadratic Formula
Lesson IDMath Lesson TitleLessonVideo
Lesson
9.6.1Quadratic Formula Definition
9.6.2The Meaning of Discriminant
9.6.3Quadratic Equations in Practice
9.6.4Vieta's Formulas

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