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Welcome to our Math lesson on The Synthetic Division Method of Polynomials, this is the first lesson of our suite of math lessons covering the topic of Solutions for Polynomial Equations, you can find links to the other lessons within this tutorial and access additional Math learning resources below this lesson.
The synthetic division method is a method used to divide polynomials in a much simpler way compared to the long division method explained in tutorial 11.2. The condition to perform a synthetic division is to have a linear polynomial as a divisor, i.e. the divisor Q(x) of the polynomial P(x) must have the form mx ± n, where m is a coefficient and n a constant.
As stated in the previous tutorial, we may write the division of two polynomials as
where S(x) is the quotient polynomial and R(x) is the remainder polynomial.
For example, if P(x) = x2 + 4x + 7, we can write it as
Taking Q(x) = x + 1 yields
where
S(x) = x + 3 and R(x) = 4/(x + 1)
The procedure to perform the synthetic division is as follows:
Step 1: Write down the coefficients and the constant of the original polynomial P(x) at the place where we write the dividend when using the long division method. In addition, we write the zero of the divisor Q(x) in the place where we put the divisor in the long division method. In our example, we have P(x) = x2 + 4x + 7 and Q(x) = x + 1. Thus, we write 1, 4 and 7 in the upper part of the scheme and -1 aside (because if x + 1 = 0 then x = -1).
Step 2: Bring the leading coefficient of the original polynomial to the bottom row.
Step 3: Multiply the leading coefficient of the polynomial with the zero of the divisor and write down the result in the middle row below the second coefficient.
Step 4: Add the numbers in the second column and write down the result in the bottom row, next to the leading coefficient.
Step 5: Repeat the procedure explained in step 3 but this time using the new number.
Step 6: Repeat the procedure explained in step 4 but this time using the new number.
Step 7: Since there are no more operations to do, the last number obtained gives the remainder of the division (here it is 4). Hence, the remainder is R(x) = 4. On the other hand, the number preceding it represents the constant of the quotient (here it is 3) and the number preceding it, the last coefficient of the quotient polynomial and so on. Hence, the quotient is S(x) = x + 3. Finally, since -1 is a zero of the divisor, we have Q(x) = x + 1. Therefore, since the general form of a polynomial factorisation is
then, we have in the specific case
The following figure shows the Synthetic Division Method of Polynomials represented schematically.
Divide the polynomials below using the Synthetic Division Method and write the result as a product of factors including the remainder (if exists).
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