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Math Lesson 16.7.7 - Conclusions about the Evenness and Oddness of a Function

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Welcome to our Math lesson on Conclusions about the Evenness and Oddness of a Function, this is the seventh lesson of our suite of math lessons covering the topic of Even and Odd Functions, you can find links to the other lessons within this tutorial and access additional Math learning resources below this lesson.

Conclusions about the Evenness and Oddness of a Function

From all discussed above, we can draw the following conclusions about the evenness/oddness of a function f(x):

  • Even functions must be sought among even-degree polynomials while odd functions among odd-degree polynomials. For example, some linear functions (first-degree polynomial functions) can be odd but none of the second-degree (quadratic) polynomial functions can be odd.
  • Linear functions of the general form f(x) = ax + b are odd only for b = 0, i.e. when the graph passes through the origin. For example, f(x) = 2x is odd as b = 0 but g(x) = 2x - 1 is not odd, as b = -1.
  • Quadratic functions of the general form f(x) = ax2 + bx + c are even only for b = 0, i.e. when the vertex lies on the vertical axis. For example, f(x) = 3x2 - 2 is an even function as b = 0 but g(x) = 3x2 + 2x - 2 is not even as b = 2.
  • Cubic functions of the general form f(x) = ax3 + bx2 + cx + d are odd only for b = 0 and d = 0, i.e. when the graph passes through the origin. For example, f(x) = x3 - 5x = 0 is odd, as b = 0 and d = 0. However, g(x) = x3 - 2x2 - 5x + 1 is not odd, as b = -2 and d = 1.
  • Biquadratic functions (fourth-degree polynomial functions) of the general form f(x) = ax4 + bx3 + cx2 + dx + e is even only for b = 0 and d = 0, i.e. when the middle local minimum/maximum passes through the vertical axis. For example, f(x) = 2x4 - 5x2 - 1 is even, as b = 0 and d = 0, while g(x) = 2x4 - x3 + 5x2 + 3x - 1 is not even, as b = -1 and d = 3.

In general, odd-degree polynomial functions are only odd if the coefficients of the even-degree terms are 0 (i.e. if the even-degree terms do not exist in that function), while even-degree polynomial functions are only even if the coefficients of the odd-degree terms are 0 (i.e. if the odd-degree terms do not exist in that function).

Example 7

Determine the evenness/oddness of the following polynomial functions by analysing the coefficients/constants and confirm your solution using the graph method.

  1. f(x) = -3x5 - x2 + 1
  2. g(x) = x4 - 3x2 + 4
  3. h(x) = x7 - 2x3 + x
  4. i(x) = 5x6 - x - 4

Solution 7

  1. This is a fifth-degree polynomial function that is possibly odd. The general form of such functions is f(x) = ax5 + bx4 + cx3 + dx2 + ex + f. In order to be odd, the function f(x) must have only odd-degree terms. However, since this function contains an even-degree term (-x2), it is not odd because one of the even coefficients (the coefficient d) is not zero (it is -1).
    Indeed, looking at the graph of this function (shown below) it is clear that it is not odd because it has no origin symmetry.Math Tutorials: Even and Odd Functions Example
  2. This is a fourth-degree polynomial (biquadratic) function that is possibly even. The general form of such functions is g(x) = ax4 + bx3 + cx2 + dx + e. In order to be even, the function g(x) must have only even-degree terms. This occurs only if it has no odd-term coefficients. This is precisely the case in this example (b = 0 and d = 0), so the function g(x) is even.
    Indeed, looking at the graph of this function (shown below) it is clear that it is even because it has a horizontal symmetry.Math Tutorials: Even and Odd Functions Example
  3. This is a seventh-degree polynomial function that is possibly odd. The general form of such functions is h(x) = ax7 + bx6 + cx5 + dx4 + ex3 + fx2 + gx + h. In order to be odd, the function h(x) must have only odd-degree terms. This occurs only if it has no even-term coefficients. This is precisely the case in this example (b = 0, d = 0, f = 0 and h = 0), so the function h(x) is odd.
    Indeed, looking at the graph of this function (shown below) it is clear that it is odd because it has an origin symmetry.Math Tutorials: Even and Odd Functions Example
  4. This is a sixth-degree polynomial function that is possibly even. The general form of such functions is i(x) = ax6 + bx5 + cx4 + dx3 + ex2 + fx + g. In order to be even, the function i(x) must have only even-degree terms. This occurs only if it has no odd-term coefficients. However, this is not the case, as there is a non-zero odd-term coefficient (f = -1). Therefore, the function i(x) is not even.
    Indeed, looking at the graph of this function (shown below) it is clear that it is not even because it has no horizontal symmetry.Math Tutorials: Even and Odd Functions Example

You have reached the end of Math lesson 16.7.7 Conclusions about the Evenness and Oddness of a Function. There are 10 lessons in this physics tutorial covering Even and Odd Functions, you can access all the lessons from this tutorial below.

More Even and Odd Functions Lessons and Learning Resources

Functions Learning Material
Tutorial IDMath Tutorial TitleTutorialVideo
Tutorial
Revision
Notes
Revision
Questions
16.7Even and Odd Functions
Lesson IDMath Lesson TitleLessonVideo
Lesson
16.7.1Definition of Even Functions
16.7.2How to Prove the Evenness of a Function Analytically
16.7.3The Graph of Even Functions
16.7.4Definition of Odd Functions
16.7.5Proving the Oddness of a Function Analytically
16.7.6The Graph of Odd Functions
16.7.7Conclusions about the Evenness and Oddness of a Function
16.7.8What If a Function is Neither Even Nor Odd?
16.7.9Properties of Even Functions
16.7.10Properties of Odd Functions

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