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Welcome to our Math lesson on What does the Sign of the Coefficient "a" Indicate for the Parabola?, this is the fifth lesson of our suite of math lessons covering the topic of Quadratic Graphs Part One, you can find links to the other lessons within this tutorial and access additional Math learning resources below this lesson.
The sign of the coefficient 'a' is very important in understanding the direction of a parabola formed by a quadratic equation. Thus, if this coefficient is positive, the parabola has the arms up, as occurred in all examples we have discussed so far. In such cases, the parabola has a minimum, which corresponds to the vertex V. On the other hand, when the coefficient 'a' is negative, the arms of the parabola are directed downwards and the parabola has a maximum at the vertex point V. The solution is the same as in the previous cases.
Let's consider an example where the coefficient a is negative to clarify this point. For example, let's consider the quadratic equation
where a = -1, b = -5 and c = 6. The discriminant Δ therefore is
Thus, the roots of the quadratic equation -x2 -5x + 6 = 0, which correspond to the x-intercepts of the corresponding parabola are
and
The two x-intercepts therefore are: A(1, 0) and B(-3, 0).
Now, let's deal with the vertex point V. we have
and
Thus, the vertex V is at V(-5, 4, 9/4).
Now, let's find the y-intercept C of the graph. Thus, for x = 0, we have
Therefore, the y-intercept is at C(0, 6).
The symmetrical point to C (which we call D) is at xD = -5, because from the half segment formula
we obtain
Thus,
The y-coordinate of point D therefore is
Hence, the point D is at (-5, 6).
Inserting all these five points: A(1, 0), B(-3, 0), in the same coordinates system and connecting them smoothly yields a parabola. With the five points found above the graph actually lies from zero and above, but if we continue drawing the line below zero in the same way, we obtain the following graph:
Plot the graph of the following quadratic equation.
We have a = -2, b = -5 and c = -2. The discriminant Δ is
Since the discriminant is positive, the equation has two roots. This means the corresponding parabola has two x-intercepts A and B, where:
and
Therefore, the two x-intercepts have the coordinates A(-1/2, 0) and B(-2, 0).
Again, the vertex V has the coordinates
and
Hence, the vertex is at V(-5/4, 9/8).
The y-intercept C is at xC = 0 and yC = c = -2. Hence, this point has the coordinates C(0, -2).
Last, let's find the symmetrical point of C, i.e. of point D. We know from the midpoint formula that
Substituting the known values, yields
Thus,
Therefore, since the y-coordinate of point D is the same as that of point C, we have D(-5/2, -2).
Now, let's plot the graph based on the above five points: A(-1/2, 0), B(-2, 0), C(0, -2), D(-5/2, -2) and V(-5/4, 9// 8/).
You have reached the end of Math lesson 15.1.5 What does the Sign of the Coefficient "a" Indicate for the Parabola?. There are 6 lessons in this physics tutorial covering Quadratic Graphs Part One, you can access all the lessons from this tutorial below.
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