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Math Lesson 15.1.5 - What does the Sign of the Coefficient "a" Indicate for the Parabola?

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Welcome to our Math lesson on What does the Sign of the Coefficient "a" Indicate for the Parabola?, this is the fifth lesson of our suite of math lessons covering the topic of Quadratic Graphs Part One, you can find links to the other lessons within this tutorial and access additional Math learning resources below this lesson.

What does the Sign of the Coefficient "a" Indicate for the Parabola?

The sign of the coefficient 'a' is very important in understanding the direction of a parabola formed by a quadratic equation. Thus, if this coefficient is positive, the parabola has the arms up, as occurred in all examples we have discussed so far. In such cases, the parabola has a minimum, which corresponds to the vertex V. On the other hand, when the coefficient 'a' is negative, the arms of the parabola are directed downwards and the parabola has a maximum at the vertex point V. The solution is the same as in the previous cases.

Let's consider an example where the coefficient a is negative to clarify this point. For example, let's consider the quadratic equation

y = -x2 - 5x + 6

where a = -1, b = -5 and c = 6. The discriminant Δ therefore is

∆ = b2 - 4ac
= (-5)2 - 4 ∙ (-1) ∙ 6
= 25 + 24
= 49

Thus, the roots of the quadratic equation -x2 -5x + 6 = 0, which correspond to the x-intercepts of the corresponding parabola are

xA = -b - √∆/2a
= -(-5) - √49/2 ∙ (-1)
= 5 - 7/-2
= -2/-2
= 1

and

xA = -b + √∆/2a
= -(-5) + √49/2 ∙ (-1)
= 5 + 7/-2
= 6/-2
= -3

The two x-intercepts therefore are: A(1, 0) and B(-3, 0).

Now, let's deal with the vertex point V. we have

xV = -b/2a
= - (-5)/2 ∙ (-1)
= -5/2

and

yV = -/4a
= -49/4 ∙ (-1)
= 49/4

Thus, the vertex V is at V(-5, 4, 9/4).

Now, let's find the y-intercept C of the graph. Thus, for x = 0, we have

yC = -(-5)2 - 5 ∙ (-5) + 6
= -25 + 25 + 6
= 6

Therefore, the y-intercept is at C(0, 6).

The symmetrical point to C (which we call D) is at xD = -5, because from the half segment formula

xV = xC + xD/2

we obtain

-5/2 = 0 + xD/2

Thus,

xD = -5

The y-coordinate of point D therefore is

yD = -(-5)2 - 5 ∙ (-5) + 6
= -25 + 25 + 6
= 6

Hence, the point D is at (-5, 6).

Inserting all these five points: A(1, 0), B(-3, 0), in the same coordinates system and connecting them smoothly yields a parabola. With the five points found above the graph actually lies from zero and above, but if we continue drawing the line below zero in the same way, we obtain the following graph:

Math Tutorials: Quadratic Graphs Part One Example

Example 4

Plot the graph of the following quadratic equation.

y = -2x2 - 5x - 2

Solution 4

We have a = -2, b = -5 and c = -2. The discriminant Δ is

∆ = b2 - 4ac
= (-5)2 - 4 ∙ (-2) ∙ (-2)
= 25 - 16
= 9

Since the discriminant is positive, the equation has two roots. This means the corresponding parabola has two x-intercepts A and B, where:

xA = -b - √∆/2a
= -(-5) - √9/2 ∙ (-2)
= 5 - 3/-4
= 2/-4
= -1/2

and

xB = -b + √∆/2a
= -(-5) + √9/2 ∙ (-2)
= 5 + 3/-4
= 8/-4
= -2

Therefore, the two x-intercepts have the coordinates A(-1/2, 0) and B(-2, 0).

Again, the vertex V has the coordinates

xV = -b/2a
= -(-5)/2 ∙ (-2)
= -5/4

and

yV = -∆/4a
= -9/4 ∙ (-2)
= 9/8

Hence, the vertex is at V(-5/4, 9/8).

The y-intercept C is at xC = 0 and yC = c = -2. Hence, this point has the coordinates C(0, -2).

Last, let's find the symmetrical point of C, i.e. of point D. We know from the midpoint formula that

xV = xC + xD/2

Substituting the known values, yields

-5/4 = 0 + xD/2

Thus,

xD = -5/2

Therefore, since the y-coordinate of point D is the same as that of point C, we have D(-5/2, -2).

Now, let's plot the graph based on the above five points: A(-1/2, 0), B(-2, 0), C(0, -2), D(-5/2, -2) and V(-5/4, 9// 8/).

Math Tutorials: Quadratic Graphs Part One Example

You have reached the end of Math lesson 15.1.5 What does the Sign of the Coefficient "a" Indicate for the Parabola?. There are 6 lessons in this physics tutorial covering Quadratic Graphs Part One, you can access all the lessons from this tutorial below.

More Quadratic Graphs Part One Lessons and Learning Resources

Types of Graphs Learning Material
Tutorial IDMath Tutorial TitleTutorialVideo
Tutorial
Revision
Notes
Revision
Questions
15.1Quadratic Graphs Part One
Lesson IDMath Lesson TitleLessonVideo
Lesson
15.1.1Recalling Quadratic Equations
15.1.2Plotting Quadratic Graphs
15.1.3Is there an easy way to plot a Quadratic Graph?
15.1.4What if the Discriminant is Zero or Negative?
15.1.5What does the Sign of the Coefficient "a" Indicate for the Parabola?
15.1.6Finding the Equation of a Parabola from its Graph

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